.53x^2-7x-30=0

Solution for .53x^2-7x-30=0 equation:

.53x^2-7x-30=0

a = .53; b = -7; c = -30;
Δ = b2-4ac
Δ = -72-4·.53·(-30)
Δ = 112.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{112.6}}{2*.53}=\frac{7-\sqrt{112.6}}{1.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{112.6}}{2*.53}=\frac{7+\sqrt{112.6}}{1.06}
$